AB=BC = 16 cm c. Jika tingginya = 60 berapa luas permukaan
Tinggi Sisi Tegak
x² = 60² - 8²
x² = (60 + 8) (60 - 8)
x² = 68 (52)
x² = 3.536
x = 4√221
x = 59,46
Luas Permukaan
= La + 4 Lst
= (16)² + 4 × (½ × 16 × 4√221)
= 256 + (2 × 16 × 4√221)
= 256 + 128√221
= 256 + 1.902,72
= 2. 158,72 cm²
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